-3v^2-33v-84=0

Solution for -3v^2-33v-84=0 equation:

-3v^2-33v-84=0

a = -3; b = -33; c = -84;
Δ = b2-4ac
Δ = -332-4·(-3)·(-84)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-9}{2*-3}=\frac{24}{-6}
=-4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+9}{2*-3}=\frac{42}{-6}
=-7
$